go语言易错题第二道for循环中使用指针

以下代码有什么问题，说明原因

package main
import (
    "fmt"
)
type student struct {
    Name string
    Age  int
}
func pase_student() map[string]*student {
    m := make(map[string]*student)
    stus := []student{
        {Name: "zhou", Age: 24},
        {Name: "li", Age: 23},
        {Name: "wang", Age: 22},
    }
    for _, stu := range stus {
        m[stu.Name] = &stu
    }
    return m
}
func main() {
    students := pase_student()
    for k, v := range students {
        fmt.Printf("key=%s,value=%v \n", k, v)
    }
}

答：输出的均是相同的值：&{wang 22}

解析 因为for遍历时，变量stu指针不变，每次遍历仅进行struct值拷贝，故m[stu.Name]=&stu实际上一致指向同一个指针，最终该指针的值为遍历的最后一个struct的值拷贝。形同如下代码：

var stu student 
for _, stu = range stus {
    m[stu.Name] = &stu
} 

修正方案，取数组中原始值的指针：

for i, _ := range stus {
    stu:=stus[i]
    m[stu.Name] = &stu
}

参考：
www.topgoer.com
https://yushuangqi.com/blog/2017/golang-mian-shi-ti-da-an-yujie-xi.html